HELP, Chemistry Empirical and molecular formulas?

Question

Caproic acid (molar mass = 116g/mol) is composed of C, H and O atoms. Combustion of a 0.225g sample produces 0.512g CO2 (carbon dioxide) and 0.209 H20 (water).
a) Find empirical formula of caproic acid
b) Find molecular formula of caproic acid

Answer 1

0.225g sample <==> 0.00194 mol
0.209 H20 <==> 0.0116 mol H2O ==> 0.0232 mol H atoms
0.0232/0.00194 = 11.97 ≈ 12 (# of H atoms in one molecule of Caproic acid)
0.512g CO2 <==> 0.0116 mol CO2
0.0116/0.00194 = 5.99 ≈ 6 (# of C atoms in one molecule of Caproic acid)
The number of O in one molecule of Caproic acid is:
(116 - 6*12 - 12*1)/16 = 32/16 = 2
The answer to both A and B is: C6H12O2