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Question

One piece of copper jewelry at 111°C has exactly twice the mass of another piece, which is at 48.0°C. Both pieces are placed inside a calorimeter whose heat capacity is negligible. What is the final temperature inside the calorimeter (c of copper = 0.387 J/g·K)?

Answer 1

Use algebra for understanding--let the final temperature be T.
it is clear that:
2(111 - T) = T - 48
Solve it for T
arithmetically using the same concept, you can do:
111 - (111 - 48)/3 = 90
90°C is the answer!