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find equivalant fractions with LCD as the denominator...

1. 1/2 and 2/3

2. 2/11 and 3/22

3. 13/19 and 11/57

4. 23/30 and 17/60

2007-10-20 07:39:27 · 4 answers · asked by kristine z 2 in Education & Reference Homework Help

4 answers

It would be wrong for anyone to do these for you, especially as they look pretty easy. However maybe a hint or two would be okay.

LCD = Lowest Common Denominator

You want pairs of fractions with the same denominator, and then you want that to be as low as possible.

You could get the same denominator by multiplying each fraction top and bottom by the denominator of the other fraction, of course that wouldn't necessarily be the lowest, but it is in the first case so that shouldn't be too hard for you.

It might be that one of the fractions is already correct and you just have to match the other to it. That accounts for the second, third and fourth examples, which is correct ... come on you only have a choice of two and it's the same each time.

Hope this helps.

2007-10-20 08:00:43 · answer #1 · answered by Nigel K 3 · 1 0

1. 3/6 and 4/6

2. 4/22 and 3/22

3. 39/57 and 11/57

4. 46/60 and 17/60

In 2-4 the LCD is already in the problem. Is this what you mean?

2007-10-20 14:49:16 · answer #2 · answered by cjvw622 7 · 0 0

To find the LCD, try looking at your highest denominator. See if your lower one can go into it evenly. If it can, then the higher one will be your LCD. If not then try multiplying the higher one by 2. If the lower denominator still does not go into the one multiplied by 2 then try multiplying by 3 then 4 and then 5 until the lower denominator can go into it.
In #1 you have 1/2 and 2/3. Of course 2 does not go into 3 evenly so multiply 3 (the higher denominator) by 2. And since you get 6 by doubling it and 2 can go into 6, then 6 is your LCD. Then you multiply each denominator by whatever number to equal 6 and multiply the numerator by the same number. Ex. 1/2 (multiply by 3 to get your LCD 6 and multiply your numerator by 3 also) = 3/6 and 2/3= 4/6! Let's try #2. You have 2/11 and 3/22. Well 11 goes into 22 evenly so all you have to do is multiply 2 and 11 by 2. 2/11= 4/22 and 3/22= 3/22, lol! Try doing that for each problem.

2007-10-20 15:56:29 · answer #3 · answered by Stepahnie 3 · 0 0

I won't do the homework - but I'll give you some ideas on how to solve.

1) What's the lowest number that is divisible by both 2 and 3? Use that as your denominator, and write equivalent fractions for 1/2 and for 2/3.

2) What's the lowest number that is divisible by both 11 and 22? Use that as your denominator, and write equivalent fractions for 2/11 and 3/22.

3) What's the lowest number that is divisible by both 19 and 57? Use that as your denominator, and write equivalent fractions for 13/19 and 11/57.

4) What is the lowest number that is divisible by both 30 and 60? Use that as your denominator, and write equivalent fractions for 23/30 and 17/60.

(HINT: a number is always divisible by itself. For instance - 57 is divisible by 57.)

2007-10-20 14:49:25 · answer #4 · answered by wibelle37 4 · 1 0

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