Algebra II Question?

Question

Consider the two equations:

a = k(m)^-1

and

b = k(m)^1

What does "k" equal and how do you find it?

Answer 1

You have some superflous parentheses, but if I read what you have typed at face value, then the first equation is

a=k/m (since m^-1 is the same as 1/m).

From this we get

m=k/a.
substitute this into the second equation and get

b=(k^2)/a

so k^2=ab,

or k= + or - the square root of ab.

Answer 2

a = k/m^1
b= km^1
so k can be any # as ong as m =1
but if m = more then 1 then k should be the same # as m

Answer 3

a = k(m)^-1

and

b = k(m)^1

=> a*b = k(m)^-1 * k(m)^1 = 1

not enough info