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So I have .033 moles of HCL and .016 moles of Mg how do I find the ratio?
I know it's mole of HCl/mole of Mg but that's not correct, maybe it's the form you have to write it in?

2007-10-20 06:06:09 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

HCl : Mg :: 0.033 : 0.016

Take the smallest molar value (0.016) and divide it into itself and into the other ratios,

HCl : Mg :: 0.033/0.016 : 0.016/0.016
HCl : Mg :: 2.0625 : 1.0

Then adjust to nearest whole numbers.

HCl : Mg :: 2 : 1

In words, Hcl is in the ratio of two to Mg in the ratio of one.

2007-10-20 06:26:29 · answer #1 · answered by lenpol7 7 · 0 0

I'm not sure what you want, but the reaction goes like this:

Mg + 2 HCl --> MgCl2 + H2

The molar ratio between the two substances if one mole of Mg per two moles of HCl.

So, your 0.016 moles of Mg would require 0.032 moles of HCl to fully react, thereby leaving 0.001 mole of HCl remaining.

HTH

2007-10-20 13:13:28 · answer #2 · answered by ChemTeam 7 · 0 0

The way it's normally written is 2:1 HCl:Mg.

2007-10-20 13:11:39 · answer #3 · answered by Gervald F 7 · 0 0

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