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Explain how Newtons law 2 contains Newtons law 1 within it? (in other words, how does Newtons law 2 “include” Newtons law 1. How is Newtons law 1 is just a special case of the Newtons law 2 relationship?)

please answer, thanks

2007-10-20 04:22:18 · 5 answers · asked by Anonymous in Science & Mathematics Physics

5 answers

Newton's first law is superfluous or redundant.

Newton's second law includes first law.

Newton's second law states that the force equals the rate of change in momentum.

If there is no change in momentum then the force is zero.
Conversely if there is no force then there is no change in momentum.

If the initial momentum is zero and if there is no change in momentum then the momentum will remain the same as zero.

If the initial momentum is not zero and if there is no change in momentum then the momentum will remain the same as its initial momentum which was not zero.

Thus this is the first law which is a consequence of second law.

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In mathematics we have the phrases like" If and only if" and" Necessary and sufficient conditions".

Hence a deep analysis is required, which warrants us from saying that Newton's second law is inclusive of first law.

However we can have a formal statement as above.
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2007-10-20 05:38:18 · answer #1 · answered by Pearlsawme 7 · 0 0

Law 1 is about inertia. A measure of that is momentum p = mv. As long as v = constant, there are no forces on the mass m and inertia keeps the mass chugging ahead (or still if v = 0, which is also a constant).

Law 2 is related because we can now say, but what if v <> constant? In which case, we have dp/dt = d(mv)/dt = dm/dt v + m dv/dt = dm/dt v + ma. d*/dt means change in * over time. And as we all know, a change in velocity over time (dv/dt = a) is called acceleration.

As mass is constant in many, if not most cases, dm/dt = 0; so we have the world famous and highly regarded f = ma. And there you have it, it takes a net force f to overcome inertia and change momentum. So, Law 2 is a "special case" of Law 1 in that it reverts to p = mv when v = constant (the special case).

By the way, Law 3 is related to Laws 1 and 2 also. In fact, when you get down to it, Newton only did variations on theme with Laws 2 and 3.

2007-10-20 04:45:04 · answer #2 · answered by oldprof 7 · 0 0

Newton's First Law says that an object in motion tends to remain in motion etc. aka. The object has a constant velocity, even if it is zero. It is not accelerating or decelerating. Enter F=ma (second law) You have to accelerate it to stop/start and If you're accelerating it, it will be a Force = ma. "The external force" mentioned in First law

2007-10-20 04:28:40 · answer #3 · answered by Anonymous · 0 0

the 1st part of your fact is right. F = MA yet while F = 0 potential there is no acceleration meaning it turns into M*A = 0. it relatively is while there is no acceleration, no velocity or purely the object isn't being acted by making use of any stress. the 1st regulation states: AN merchandise would not flow except ACTED UPON by making use of A stress. AN merchandise WILL save shifting IN A right this moment LINE AND a persevering with velocity except TAMPERED WITH by making use of A stress. the 2nd regulation is ordinarily used while speaking approximately products in action, say products falling down a tall development, ameliorations in velocity by way of fact the object quickens at the same time as the 1st regulation is approximately products that do nove flow or are actually not changing their velocity.

2016-10-07 06:57:20 · answer #4 · answered by ? 4 · 0 0

(i) Newton's first law states that every body continues to in its state of rest or of uniform motion in a straight line unless it uis compelled by an external force to change that state of rest or of uniform motion.
(ii) Second law states that the rate of change of momentum is directly proportional to the impressed force(the external force mentioned in the first law) and takes place the direction of the force.
From this law we can derive the relation , F = ma.

2007-10-20 04:51:34 · answer #5 · answered by Joymash 6 · 0 0

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