express 2x / (x^2 - 2) in partial fractions?

Question

first one to answer it correctly gets a prize =)

Answer 1

2x / (x^2 - 2)
= A / (x - sqrt(2))+ B/(x + sqrt(2))

2x=A(x +sqrt(2))+B (x - sqrt(2))

A+B=2
sqrt(2)(A-B)=0

A=1
B=1
2x / (x^2 - 2)
= 1 / (x - sqrt(2))+ 1/(x + sqrt(2))

Answer 2

I don't believe you can break x^2-2 apart and the power of x is less than that of x^2, so it's already in the correct form.

Oh yeah, square roots. OK, so there's no pretty way to break it apart...