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what is the approach through first principles?

2007-10-20 03:38:08 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

The formula to be used is d/dx e^u = e^u d/dx(u).
Thus, if
y = e^(x^2)
y' = e^(x^2) d/dx(x^2)
= e^(x^2)*2x
= 2xe^(x^2)

2007-10-20 03:43:55 · answer #1 · answered by tootoot 3 · 0 0

let u=x^2
the derivative of e^x is e^x
y=e^u
dy/dx=e^u(du/dx)
=e^u times (2x)
=2xe^(x^2)

2007-10-20 10:55:35 · answer #2 · answered by cidyah 7 · 0 0

d e ^ f(x) / dx = f '(x) * e^f(x)

'differentiate by parts'

2007-10-20 10:43:08 · answer #3 · answered by gjmb1960 7 · 0 0

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