6x + 8 - 12x + 15
-6x + 23
2007-10-20 03:22:47
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answer #1
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answered by hemant_gome 2
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2(3x+4) - 3(4x-5)
Consider only first part 2(3x+4)
Here the sign between 2 and (3x + 4) is multiplication
so to open the bracket, multiply each and every term in the bracket with it's signs. Here only 2 terms are there in the bracket
So 2(3x+4) = 2 × 3 x + 2 × 4 = 6 x + 8
Now second second part (– 3) × 4 x + (–3)(–5)
= – 12 x + 15
2(3x+4) - 3(4x-5) = 6 x + 8 – 12 x + 15
= 6 x – 12 x + 8 + 15 ----------- rearranging the terms
Now 6 x – 12 x here 6 x smaller than 12 x you cant not subtract directly. In such cases do subtraction and keep the sign of greater number in the answer.
so 6x – 12 x = – 6x
6 x – 12 x + 8 + 15 = – 6x + 23
2007-10-20 03:32:43
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answer #2
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answered by Pranil 7
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Expand And Simplify
2016-11-16 07:10:35
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answer #3
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answered by ? 4
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2(3x+4) - 3(4x-5)
Expand
6x + 8 - 12x +15
Combine x's and numbers
-6x + 23
.
2007-10-20 03:24:08
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answer #4
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answered by Robert L 7
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This Site Might Help You.
RE:
How to expand and simplify?
Hi to all
It's been a while since I have done maths!
How do you expand and simplify?
e.g. 2(3x+4) - 3(4x-5)
Is the answer 18x-15??
Or do you take away the x's instead of adding??
Thankyou
2015-08-16 07:11:22
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answer #5
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answered by Anonymous
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Do the multiplucation first and you get
6x+8-12x+15 Add the similar terms next tp simplify
-6x+23 is the result
2007-10-20 03:24:57
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answer #6
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answered by frozen 5
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salam ninja
You already got a lot of answers, but here is one more.
2(3x+4) - 3(4x-5) = 6x + 8 - 12x + 15 = -6x + 23
2007-10-20 03:56:40
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answer #7
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answered by swd 6
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do it slowly
2(3x+4)-3(4x-5)
Open the brackets
=6x +8 -12x+15
Rearrange the elements
=6x-12x + 8+15
=-6x + 23
2007-10-20 03:23:22
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answer #8
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answered by mwanahamisi 3
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do it slowly
2(3x+4)-3(4x-5)
use destribuitive property
=6x +8 -12x+15
add like terms
=6x-12x + 8+15
=-6x + 23
choose me as best : )
2007-10-20 06:26:25
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answer #9
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answered by The Answer 3
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First you expand the bracets seperately:
6x + 8 - 12x + 15
then you colect like terms:
-6x + 23
That's it...
2007-10-20 03:25:08
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answer #10
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answered by nobody 2
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