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3) An ammeter uses a galvanometer and a shunt resistance of .20 W. The galvanometer has an internal resistance of 100 W. If 2.0A pass through the ammeter how much current enters the galvanometer?


4) A galvanometer has an internal resistance of 20 W and a full scale deflection 0.50 mA. If it has a 2.0 m W shunt resistor to make it an ammeter what is the full scale current? Draw the circuit.

2007-10-19 17:55:17 · 6 answers · asked by wzerocx 2 in Science & Mathematics Physics

an explanation please

2007-10-19 18:18:16 · update #1

6 answers

Req = 0.2*100/100.2 ≈ 0.1996008 Ω
V = IReq = 2.0*0.1996008 ≈ 0.3992016 V
Ig = V/Rg = 0.3992016/100 ≈ 3.992016 mA

2007-10-19 18:37:38 · answer #1 · answered by Helmut 7 · 0 0

3) The curent through the shunt resistance = 1.996 Amps
The current through the Galvanometer = 0.003992 Amps

2007-10-19 20:02:47 · answer #2 · answered by Joymash 6 · 0 0

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2016-10-07 06:32:36 · answer #3 · answered by devoti 4 · 0 0

internal resistance of 20 w ?

whats this ?

2007-10-19 20:28:38 · answer #4 · answered by JavaScript_Junkie 6 · 0 0

3) .4 W
20 W

2007-10-19 18:19:44 · answer #5 · answered by Anonymous · 0 0

3) 1.667A

4)5000.5A......connect it parallelly

2007-10-19 18:12:30 · answer #6 · answered by oyyo 2 · 0 0

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