If a 30 cm long wrench is used what is the magnitude of the force required when the force is 53ø to the wrench

Question

The bolts on a car wheel require tightening to a torque of 90 Núm is the beginning of the question so it should read
The bolts on a car wheel require tightening to a torque of 90 Núm. If a 30 cm long wrench is used what is the magnitude of the force required when the force is 53ø to the wrench

Answer 1

torque = r*F*sin (theta)

r = length of wrench
theta = angle between the force and the wrench*
sin(theta)= 53

F = torque/r sin(theta) = 90 N-m/(0.3m*sin(53))

final answer should be 375.64 and when rounded should be 380 N.

Know that the sin is in place because it runs perpendicular to the wrench!!!
~Early physics~

Answer 2

torque = r*F*sin (theta)

r = length of wrench
theta = angle between the force and the wrench*

*The sin term is present because that's the component of the force that's perpedicular to the wrench/axis of rotation

F = torque/r sin(theta) = 90 N-m/(0.3m*sin(58))

= 353.75 N