2007-10-19 16:52:48 · 5 answers · asked by ausomadam 1 in Science & Mathematics ➔ Mathematics
You know that the quadratic equation only has 1 root for x
(x+2)^2 = 0 = x^2 + 4x + 4
x = -2
So you can tell the discriminant is 0.
Or you can just do b^2-4ac:
b = 4, a = 1, c = 4
(4)^2 - 4(1)(4) = 16 - 16 = 0
Discriminant = 0
2007-10-19 17:00:02 · answer #1 · answered by UnknownD 6 · 1⤊ 0⤋
discriminant = b^2-4ac
= 4^2 -4(1)(4) = 16-16 = 0
2007-10-20 00:00:54 · answer #2 · answered by ironduke8159 7 · 1⤊ 0⤋
discriminant ==> -b/2a
b = 4
a = 1
-b/2a = -4/2(1) = -4/2 = -2
This means that there are 2 solutions b/c the discriminant is less than 0...
2007-10-19 23:56:56 · answer #3 · answered by sayamiam 6 · 0⤊ 1⤋
(x + 2)^2 = x^2 + 4x + 4 = 0
x = -2
2007-10-20 00:01:20 · answer #4 · answered by M S 2 · 0⤊ 0⤋
X=-4-+SR(4^2 -4*1*4) [QUADRATIC FORMULA]
/2*1 {SR mean SQUAR ROOT}
X=-4-+SR(16-16)
/2
X=-4 [BECAUSE SR OF 0 IS 0]
/2
X=-2 (ANS)
2007-10-20 00:20:10 · answer #5 · answered by RIK 2 · 0⤊ 0⤋