find the real solutions of the equation?

1 ⤊

x^5/4-4x^1/4=0

2007-10-19 15:53:23 · 3 answers · asked by Dill K 1 in Science & Mathematics ➔ Mathematics

x^5/4 = 4x^1/4 divide both sides by x^1/4

x^4/4 = 4

x = 4

x can also be zero.

2007-10-19 15:58:20 · answer #1 · answered by Kaila G 3 · 0⤊ 0⤋

Factor out x^1/4 from the equation and you get

x^1/4(x - 4) = 0

So x^1/4 = 0 or x - 4 = 0, which means the solutions are x = 0 or 4.

2007-10-19 22:58:04 · answer #2 · answered by Ian 3 · 0⤊ 0⤋

x^5/4-4x^1/4=0
x^(1/4)*(x-4)=0
x = 0 or x = 4

Doug

2007-10-19 22:59:34 · answer #3 · answered by doug_donaghue 7 · 1⤊ 0⤋