solve the formula for the indicated variable
P-3Q/7=P+5/2 (+1 ) for P
2007-10-19 15:51:57 · 8 answers · asked by Dill K 1 in Science & Mathematics ➔ Mathematics
P drops out, meaning it could have any value.
2007-10-19 15:55:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
It's kind of hard to read your formula...is this correct?
P - (3Q) / 7 = P + 5/2 (1)
Because the P's cancel out.
2007-10-19 15:55:35 · answer #2 · answered by Muff 3 · 0⤊ 0⤋
P-3Q/7=P+5/2(+1)
P=3Q/7+P+5/2(+1)
Subtract P. and you get:
0=3Q/7+5/2(+1)
the answer is undefined.
2007-10-19 15:56:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
If the last part reads (P plus five) over two, plus one, I would multiply each term by 14, which eliminates the fractions.
New equation...
14P-6Q=7(P+5)+14
14P-6Q=7P+49
7P=6Q+49
P=(6q/7)+7
If the last part reads P plus five halves plus one, I would multiply each term by 14, which eliminates the fractions.
New equation...
14p-6Q=14P+35+14
Note the P's cancel each other out, leaving you with
-6Q=49
You can not solve for P.
2007-10-19 15:59:53 · answer #4 · answered by RickSus R 5 · 0⤊ 0⤋
(P-3Q)/7=(P+5)/2 (+1 ) <-- you must mean this
Multiply both sides by 14 getting:
2P - 6Q = 7P +35 +14
2P-7P = 6Q +49
-5P = 6Q+49
P = -(6Q+49)/5
2007-10-19 16:00:01 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
Hehehe. This must be a type since P can assume any value at all.
Doug
2007-10-19 15:56:50 · answer #6 · answered by doug_donaghue 7 · 0⤊ 0⤋
Okay I'm 12 and that's easy. Do you want me to find P or what?
I'll edit my answer when you add deatails
2007-10-19 15:54:48 · answer #7 · answered by Jeni 2 · 0⤊ 1⤋
can u retype ur question plzz .. thankx
2007-10-19 15:55:32 · answer #8 · answered by Anonymous · 0⤊ 0⤋