how do you find the predicted boiling point of water? what is the equation?

Answer 1

prediction from first principles (quantum mechanics) is unfortunately intractable.

at the boiling point, the equilibrium vapor pressure is equal to the atmospheric pressure. there are various equations for the equilibrium vapor pressure of water, the simplest is the Clausius-Clapeyron relation:

ln(P2/P1) = dHvap/R * (1/T1 - 1/T2)

where P is equilibrium vapor pressure, dHvap is the enthalpy of vaporisation, R is the gas constant and T is (absolute) temperature. to use this equation you need to know two of the following:

-the enthalpy of vaporisation
-vapor pressure P1 at temperature T1
-vapor pressure P2 at temperature T2

there are also simple empirical equations for the boiling point of water:

http://en.wikipedia.org/wiki/Vapor_pressure#Water_vapor_pressure

you can also take account of colligative properties as mentioned above but this is a separate issue to what i've mentioned

Answer 2

The equation is
change in boiling point = iKbm where i = van't hoff factor which is essentially the number of dissociated particles, and m= the molarity of the added stuff. Kb = a constant related to the liquid, in this case, water. Elevation of the boiling point is known as a colligative property.

Answer 3

212 at sea level, it changes for each 100 ft in elevation. It will take longer to boil in time too. Check in a cook book for the other part of this,

Answer 4

PV=nRT