Working With Vector Components?

Question

I'm stuck on this Hw problem:

Find the magnitude and the direction of the velocity for each of the following sets of velocity components

1.) vx = -5 m/s and vy = -7 m/s

I got that it's 8.6 m/s at and im not sure the ________ degree from (the positive x axis)_

yea but i need the angle it makes

thanks i got it, i have another post like this but no one responded can u take a look at it and help me

Answer 1

8.6 m/s is correct

A=arctan(Vy/Vx)
A= arcTan(-7/ -5)=54.5 deg
however be careful since both x and y components are negative and must be in the third quadrant.

so
A=180+ 54.5 =234.5 deg

Answer 2

Tan θ =V y/ Vx = - 7 / -5 = 7/5

θ = 54.5° from the negative x axis

Adding 180 degree .234.5° from the positive x direction anticlockwise .

Answer 3

searching the aspects of a vector is like drawing a triangle. The vector, a cost that has both % and route, is the hypotenuse. So draw the triangle. 8m/s is the hypotenuse. the perspective between the hypotenuse and the leg it really is horzontal is 40 5 stages. to discover how lengthy the horizontal and vertical legs of your triangle we settle on to apply trig identities. Cos=adjacent/hypotenuse plug in what you've cos45degrees= adjacent/8 8(cos45)=adjacent ie horizontal leg There you in basic terms found the x aspect. that is named the x aspect because that is horizontal and runs parallel to the x axis. next with y. cos = opposite/hypotenuse cos 40 5 = y aspect / 8 8(cos 40 5) = y aspect There...