A 3-digit number, when rounded off to the nearest ten and the nearest hundred, gives 1000. what is the greatest possible value of this number?
2007-10-19 14:00:52 · 7 answers · asked by mong 3 in Science & Mathematics ➔ Mathematics
To round to the nearest 100 and get 1000, the number must be at least 950
To round to the nearest 10 and get 1000, the number must be at least 995.
But the greatest possible value, would be 999.
Sounds like a trick question to me... but 999 is your answer!
2007-10-19 14:07:41 · answer #1 · answered by sharky.mark 4 · 0⤊ 0⤋
999
2007-10-19 14:09:43 · answer #2 · answered by ♥♥felisha♥♥ 5 · 0⤊ 0⤋
999
2007-10-19 14:07:11 · answer #3 · answered by Anonymous · 0⤊ 0⤋
999
2007-10-19 14:06:49 · answer #4 · answered by Ace 2 · 0⤊ 0⤋
I guess your question is round up not round off and the value may is 445, since round up role value is >= 5. So when 445 round up given 1000.
2007-10-19 14:16:59 · answer #5 · answered by awkf 4 · 0⤊ 0⤋
initially, Mr. Wang has internet funds from the sale of $21. Then he ought to grant $a hundred decrease back to the different save. So now he's out $seventy 9 in funds (the quantity he gave to the customer who surpassed the undesirable bill) rather. He has additionally lost the inventory merchandise worth $18, bringing his entire loss to $ninety seven. the different $3 is the income he might have made if allowed to preserve the money from the sale.
2016-12-15 04:19:15 · answer #6 · answered by Anonymous · 0⤊ 0⤋
999 satisfies both conditions and is the largest
possible answer.
2007-10-19 14:38:35 · answer #7 · answered by steiner1745 7 · 0⤊ 0⤋