PHYSICS HOMEWORK PLEASE HELPppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!?

Question

A shell is fired from the ground with an initial speed of 1.54* 10^3 m/s at an initial angle of 53° to the horizontal.

(a) Neglecting air resistance, find the shell's horizontal range.

(b) Find the amount of time the shell is in motion.

Answer 1

Vx=Vcos(53)

shell's horizontal range
S=Vx (2t)
2t since total time equal twice the time to go up
and time to go up is
t=Vy/g where Vy=Vsin(53)