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A person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of vi = 16 m/s. The cliff is h = 36 m above the water's surface.

(a) How long does it take for the stone to fall to the water?

(b) With what speed does it strike the water?

2007-10-19 13:50:59 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

a) t=sqrt(2h/g)
t=sqrt(2 x 36 / 9.81)=
t=2.71 sec

b)Vy=gt=

Vy=9.81 x 2.71=26.6 m/s

V= sqrt(Vx^2 + Vy^2)
V=sqrt( 16^2 + 26.6^2)=
V=31 m/s

2007-10-20 16:13:43 · answer #1 · answered by Edward 7 · 0 0

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