How do i calculate Kinetic Friction.?

Question

i am in an 8th grade physics class and i have a science fair project due. i wanted to calculate the kinetic friction of ice but after further research, i found out that this might be harder than i anticipated. can anyone put this in a simple explanation for me?

Answer 1

Ice will melt in contact unless you conduct your experiment in an environment where the temperature is below water freezing.

To measure kinetic friction you would need to set up the experiment in such a way that you can measure forces acting on that block of ice. Say you have an incline of angle A.

Fd-f=F
Fd=mg sin(A)
f=u mg cos(A)
F=ma
now the coefficient of dynamic friction u is
u= (ma- mg sin(A))/ (mg cos(A))
u=(a - g sin(A))/ (g cos(A))

Measuring acceleration a remains a problem resolved by equipment you have available.

Have fun. Don't get frost bitten.

Answer 2

the position is the picture? Assuming that the mass m slides down the incline distance S1 with % of two.41m/s and keeps to commute distance S2 on the flat/horizontal element of the course. all of us comprehend that pressure of friction f is the pressure F that acts on mass m to sluggish it down. pressure of friction f=u’mg =ma So a=u’g or u’=a/g u’ – is the coefficient we ought to discover all of us comprehend that S2=Vt- .5at^2 also V=at (if we pass in reverce) t=V/a S2=V(V/a) - .5 a(v/a)^2 S2=V^2/a - .5 V^2/a= .5 V^2/a a=V^2/ (2 S2 ) finally u'= V^2/ (2 g S2 ) in basic terms replace the numbers u'= (2.40-one)^2/ (2 x 9.80 one x a million.9 ) u’= 0.156