A high-flying jet cruises at an altitude of 30,000 feet at a constant velocity of 700 km/h. The force of the jet engines is 40,000 N. How much air drag acts on the craft?
The only formula we were given is:
WEIGHT = MASS x GRAVITY
Thank you!
2007-10-19 12:10:27 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
could then the amount of drag be equal to the force of the engines?
2007-10-19 14:08:34 · update #1
Since the plane is not accelerating (not changing speed or alititude) the force of the drag equals the force of the engines. The lift required to hold up the weight of plane is part of the induced drag and can not be determined from the info given as no weight or mass is given.
2007-10-19 12:17:20 · answer #1 · answered by Mike1942f 7 · 2⤊ 0⤋
Fnet=ma a=acceliration=gravity m=mass F=newtons u are given unessary info so 40,000=m(9.8) do the math thats probably the answer or they just gave u the wrong formula, weight=n gravity=9.8 atleast thats wat i was taught but my formula and ur formula means the same thing, solve for m in ur case mass even though it prob has nothing to do with air resistance but u tried to do the work but the guy before me is most likely right
2007-10-19 19:20:39 · answer #2 · answered by Tuna Nuggetz 2 · 1⤊ 0⤋