What do I do?
2007-10-19 11:46:34 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It's a little hard to decipher from your question (without parentheses) but because of the way you spaced it I assume you meant for the x+3 and x-5 to be in the denominators:
..1 .... 2 ...... 7
----- - ---- = -----
x+3 . x-5 .. x+3
I'd start by subtracting 1/(x+3) from both sides:
. -2 ..... 6
----- = -----
x-5 ... x+3
Now cross multiply [essentially multiplying both sides by (x+3)(x-5)]:
-2(x+3) = 6(x-5)
Now it is pretty straight forward to solve.
-2x - 6 = 6x - 30
30 - 6 = 6x + 2x
24 = 8x
x = 3
As a double-check, see if it works when you plug in x = 3:
1/(3+3) - 2/(3-5) =? 7/(3+3)
1/6 - 2/(-2) =? 7/6
1/6 + 1 =? 7/6
7/6 = 7/6
So the answer is x = 3
2007-10-19 11:53:55 · answer #1 · answered by Puzzling 7 · 0⤊ 2⤋
through fact 2 of your words the two have a denominator of x+3, you are able to artwork with those first. Subtract a million/x+3 from the two factors of the equation. on the left part, a million/x+3 will cancel out leaving -2/x-5. on the incredible part, you will subtract the fractions (7/x+3)-(a million/x+3). Your equation will now look like this: -2/x+3=6/x+3. Now bypass multiply. One one edge of the equation you will have -2x-6=6x+18. upload 2x to the two factors of the equation. you will then have 6=8x+18. Then subtract 18 from the two factors of the equation. -12=8x. Divde the two factors by potential of 8 and you get -12/8=x, then simplify. -4/3=x which potential x=-a million a million/3. i don't be attentive to if that's good, bu i'm giving it my maximum suitable shot.
2016-10-13 05:35:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Here goes:
1/x+3 - 2/x-5 = 7/x+3
1/x +3 (-3)-1/x-5=7/x+3 (-3)
X*(1/x)-2/x-5) = (7/x)*X
-1/X-5(+5) = 7/x (+5)
-1/X (-7/x) = 7/x(-7/x) +5
-(8/x) =5
X*(-8/x) = 5(x)
-8/5 = 5x(/5)
X=(-8/5)
* Remember what you do to one side of an equation, you must also do to the other
2007-10-19 11:53:48 · answer #3 · answered by Anonymous · 0⤊ 2⤋
Mutlipty through the whole equation by x to get rid of the fractions to begin with
1 + 3x - 2 - 5x = 7 + 3x
Now combine like terms
-2x - 1 = 7 + 3x
Add 2x to both sides to get the x's on one side and subtract 7 from both sides to get the numbers alone on one side
-8 = 5x
Divide through by 5 to get the x alone
-8/5 = x
2007-10-19 11:53:30 · answer #4 · answered by Ms. Exxclusive 5 · 2⤊ 1⤋
1/(x+3) - 2/(x-5) = 7/(x+3)
(1/x+3) - (7/x+3) = (2/x+5)
-6/x+3 = 2/(x+5)
multiply with (x+3)(x-5)
-6(x-5) = 2(x+3)
-6x + 30 = 2x + 6
8x = 24
x = 3
2007-10-19 12:04:36 · answer #5 · answered by mohanrao d 7 · 1⤊ 1⤋
(x - 5) - 2(x + 3) = 7(x - 5)
x - 5 - 2x - 6 = 7x - 35
24 = 8x
x = 3
2007-10-23 07:24:00 · answer #6 · answered by Como 7 · 0⤊ 0⤋
You find the LCD first. It is (x +3)(x - 5).
Multiply each side by the LCD to get
x - 5 -2x - 6 = 7x - 35
-x -11 = 7x - 35
24 = 8x
3 =x
2007-10-19 11:56:52 · answer #7 · answered by G.V. 6 · 1⤊ 1⤋
x(1/x)+x(3/1)- x(2/x) - x(5/1) = x(7/x)+ x(3/1)
1 +3x - 2-5x=7+3x
3x- 5x-3x =7+2-1
-5x=9-1
-5x=8
-5x/-5= 8/-5
x= 8/-5
2007-10-19 12:03:09 · answer #8 · answered by Anonymous · 1⤊ 1⤋
I only left school 5 years ago. I did the higher paper and got an A... And I can't remember at all :s I hope it's coz it's late :p
2007-10-19 11:50:43 · answer #9 · answered by Belle 3 · 0⤊ 3⤋
isolate all the integers to one side of the equation, the #/x's on the other side.
keep in mind that anything over the same denominator means you can perform basic arithmetic on them on top.
then isolate the x variable to get your answer.
2007-10-19 11:51:52 · answer #10 · answered by smarty_pants 3 · 0⤊ 2⤋