Yes,
Block A = 50 kg
Block B = 100 kg
They are hanging and the string is holding them together.
The figure is nice
2007-10-19 17:54:14
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answer #2
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answered by Ilya S 3
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â thus initial potential energy (PE) of the system is that of block B, that is E=m2*g*d, where m2=100 kg,distance d=17m, g=9.8 m/s^2 gravity acceleration;
⣠final energy of the system is also E=E1+E2+E3+E4, where
E1=m1*gh is PE of m1=50 kg, h=d*sin(b) is change of level of m1 above horizontal, b is angle of incline to horizontal,
E2=0.5*m1*v^2 is KE of m1,
E3=0.5*m2*v^2 is KE of m2, v is final speed of blocks,
E4=F4*d is energy loss due to friction,
F4=μ*m1*g*cos(b) is friction force, μ=0.28,
m1*g*cos(b) is component of weight m1*g normal to the surface of incline;
⦠thus energy balance looks:
m2*g*d = m1*g*d*sinb +0.5*(m1+m2)*v^2 +μ*m1*g*cosb*d;
hence v^2= 2gd*(m2 -m1*sinb -μ*m1*cosb) /(m1+m2),
hence E2= gd*m1*(m2 -m1*sinb -μ*m1*cosb) /(m1+m2)=
= 9.8*17*50*(2 -sinb –0.28*cosb)/3 = ??? Joule
plug in angle b;
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2007-10-19 18:16:52
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answer #3
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answered by Anonymous
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i'm great a reading minds.... i see something.... something....
you want to figure out something. me thinks it something to do with inclined planes, tension, or acceleration.
2007-10-19 17:48:40
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answer #4
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answered by civil_av8r 7
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