English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

4 answers

yes....the figure is important as it shows the angels

2007-10-19 10:45:37 · answer #1 · answered by m m 3 · 0 0

Yes,

Block A = 50 kg
Block B = 100 kg

They are hanging and the string is holding them together.
The figure is nice

2007-10-19 17:54:14 · answer #2 · answered by Ilya S 3 · 0 0

☺☺☺☺☺☺☺☺
♠ thus initial potential energy (PE) of the system is that of block B, that is E=m2*g*d, where m2=100 kg,distance d=17m, g=9.8 m/s^2 gravity acceleration;
♣ final energy of the system is also E=E1+E2+E3+E4, where
E1=m1*gh is PE of m1=50 kg, h=d*sin(b) is change of level of m1 above horizontal, b is angle of incline to horizontal,
E2=0.5*m1*v^2 is KE of m1,
E3=0.5*m2*v^2 is KE of m2, v is final speed of blocks,
E4=F4*d is energy loss due to friction,
F4=μ*m1*g*cos(b) is friction force, μ=0.28,
m1*g*cos(b) is component of weight m1*g normal to the surface of incline;
♦ thus energy balance looks:
m2*g*d = m1*g*d*sinb +0.5*(m1+m2)*v^2 +μ*m1*g*cosb*d;
hence v^2= 2gd*(m2 -m1*sinb -μ*m1*cosb) /(m1+m2),
hence E2= gd*m1*(m2 -m1*sinb -μ*m1*cosb) /(m1+m2)=
= 9.8*17*50*(2 -sinb –0.28*cosb)/3 = ??? Joule
plug in angle b;
♥ you may add details to the same question later, there’s an option; it is not necessary for you to repeat the same question to put details and clarifications;
unless the solution is clear, you are welcome to ask for more details through email in answerer’s profile;

2007-10-19 18:16:52 · answer #3 · answered by Anonymous · 0 0

i'm great a reading minds.... i see something.... something....

you want to figure out something. me thinks it something to do with inclined planes, tension, or acceleration.

2007-10-19 17:48:40 · answer #4 · answered by civil_av8r 7 · 0 0

fedest.com, questions and answers