The number of pounds of
milk, M, required by a calf weighing x pounds can be estimated by the formula
M = -5 + sqrt(6.7x - 444)
Estimate the number of pounds of milk required by a calf with a weight of 300
pounds.
2007-10-19 10:01:40 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
First do 6.7 x 300 = 2010. Then subtract 444 to get 1566. The square root of that is 39.5 so take away another 5 and get about 35 pounds of milk. That is about 4 gallons.
2007-10-19 10:07:17 · answer #1 · answered by Rich Z 7 · 0⤊ 0⤋
If you have a calculator:
Multiply 6.7 by 300 (that's tuff)
Subtract 444 from that (that's real tuff)
Take the sqrt of the difference (gee, another key-stroke, that's rocket science)
Now subtract 5 from the sqrt (man, that must be 10th grade stuff)
I'll even give you an estimate of the answer, about 35.
2007-10-19 17:19:11 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋