3u2 = 8u – 5
2007-10-19 09:51:47 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3u2 = 8u – 5
3u^2 = 8u - 5
3u^2 - 8u + 5 = 0
(3u - 5)(u - 1) = 0
u = 5/3, 1
Note: Dave F factored the quadratic incorrectly
2007-10-19 09:58:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
If 3u2 = 3u^2 then add 8u-5 to both sides and you have
3u^2-8u+5=0
which can be solved using the quadratic formula.
2007-10-19 16:58:11 · answer #2 · answered by Michael G 3 · 0⤊ 0⤋
Since there is a "u squared" this is going to be a quadratic equation. That means you must make one side equal to 0 and then you can factor to find the solution.
3u^2 - 8u + 5 = 0
(3u - 1)(u - 5) = 0
3u - 1 = 0
3u = 1
u = 1/3
u - 5 = 0
u = 5
Therefore:
u = 1/3 and 5
2007-10-19 16:56:17 · answer #3 · answered by Anonymous · 0⤊ 1⤋
3u^2=8u-5
3u^2-8u+5=0
3u^2-3u-5u+5=0
3u(u-1)-5(u-1)=0
(u-1)(3u-5)=0
u=1,5/3 AN.S.
2007-10-19 16:59:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
3 u ² - 8 u + 5 = 0
(3 u - 5) (u - 1) = 0
u = 5 / 3 , u = 1
2007-10-23 14:19:28 · answer #5 · answered by Como 7 · 0⤊ 0⤋
3u^2-8u+5=0
or 3u^2-3u-5u+5=0
or 3u(u-1)-5(u-1)=0
or (3u-5)(u-1)=0
so either 3u-5=0 or u-1=0
so either u=5/3 or u=1 ans
2007-10-19 17:27:41 · answer #6 · answered by MAHAANIM07 4 · 0⤊ 0⤋
is that 3u^2
oh yeah and the guy below me got his factorization backwards
it's (3u-5)(u-1)=0
2007-10-19 16:55:07 · answer #7 · answered by sexy joker 6 · 0⤊ 0⤋