how to factor this?
-x^2 + 3x -2
2007-10-19 09:01:46 · 9 answers · asked by tmlfan 4 in Science & Mathematics ➔ Mathematics
-x^2 + 3x -2=0
First take a negative out by dividing by -1, putting a -1 in front to represent you doing so
-1[x^2-3x+2]
Find what times together = 2 and added = -3
-1 (-2) = 2
-1 - 2 = -3
These are your factors, so insert them into the equation with the -1 in front still
-1[(x-2)(x-1)]
You dont have to leave the -1 there, its more symbolic than anything :)
2007-10-19 09:04:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋
First factor out -1
-1(x^2-3x+2)
-1(x-2)(x-1)=Anwsar
2007-10-19 16:09:31 · answer #2 · answered by scide i 2 · 0⤊ 0⤋
(x-1) (-x+2)
2007-10-19 16:06:07 · answer #3 · answered by David F 5 · 0⤊ 0⤋
(-x+1)(x-2)
2007-10-19 16:06:51 · answer #4 · answered by marystoy_2000 5 · 0⤊ 0⤋
first you need to remove the negative out of the equation
-1(x^2-3x+2)
now that you done that you have to do something for me
i want to see a video of you dancing in whatever you want.
2007-10-19 16:05:51 · answer #5 · answered by fvsdf s 2 · 0⤊ 0⤋
-x^2+3x-2
-1(x^2-3x+2)..................taking -1 common from the equation
-1(x^2-2x-x+2)...............splitting the 2nd term ie.-3x into to its two factors which can be added or subtracted to obtain the 2nd term and the two factors will have to be the factors of the the product of 1st nd 3rd term ie. x^2 and 2 respectively, of the equation.
-1[x(x-2)-1(x-2)]...............taking out common
-1[(x-1)(x-2)]....................thus, factorising it.
2007-10-19 16:28:07 · answer #6 · answered by Anonymous · 0⤊ 1⤋
Another answer would be:
(1 - x)(x - 2)
or
(x - 1)(2 - x)
2007-10-19 16:06:43 · answer #7 · answered by Dave 6 · 0⤊ 0⤋
- (x² - 3x + 2)
- (x - 2)(x - 1)
2007-10-19 16:34:57 · answer #8 · answered by Como 7 · 1⤊ 0⤋
-(x^2 -3x +2) = -(x-1)(x-2).
2007-10-19 16:05:02 · answer #9 · answered by Anonymous · 0⤊ 0⤋