This question is asking for clarification on the concept that gravity is a cause of time dilation and that a black hole is the most extreme case of gravitation of which we know.
Simply stated, time dilation has been calculated to be at its maximum effect at the event horizon or "surface" of a black hole. This time dilation manifests itself in this way: An observer at the event horizon of a black hole would experience the entirety of all time of the rest of the universe in his own shortest amount of time. The difficulty that we encounter in understanding this concept is defining what the "entirety of time" is. Also, there arises the question, "What would be the observer's next moment of time, given that time no longer exists?"
Thus, for the sake of this discussion, let us make a reasonable assumption. Let us substitute a reasonable value for the quantity "the entirety of time" of 10 to the 60th power Planck time units (about 75 billion years). Let us also make the assumption that the shortest amount of time is one Planck time unit (10 to the negative 43 seconds). This we define as the maximum amount of time dilation possible.
We have stated that time dilation is at its maximum point at the event horizon of a black hole. The formula (highly simplified) is outside observer’s time divided by internal observer’s time equals the value of time dilation; similarly the rate of passage of time is related to the amount of gravity experienced by any particular observer.
Now we come to why it is commonly said that there is no time inside a black hole. If our observer moves more closely to the singularity (ignoring, for the sake of simplicity, any effects of the tremendous crushing gravity present), the observer will be in a stronger gravitational field; thus experiencing a larger value of time dilation.
However, such a calculation cannot be done. Our previous calculation already had the largest value in the numerator and the smallest value in the denominator. Yet the relationship of the gravitational field to the value of time dilation demands that either the numerator is larger or that the denominator is less.
Let us only deal with the value of the denominator for the time being. The denominator is ten to the negative forty-third power seconds. Any less would be zero and we still cannot divide by zero regardless of all our scientific advancements. More maddening than this is we would need to divide by numbers that are less than zero and that are not negative, that are not fractions, and that are not imaginary. Such math does not exist.
It is because the math cannot be done that it is said that we do not know what happens inside of a black hole. It is often erroneously stated that we do not know what happens inside a black hole because the information cannot get out; such a statement is misleading at best and conceptually infantile at least.
Stated properly, it can be said that although there is time inside a black hole, we cannot define its state with our present level of knowledge.
2007-10-20 11:41:31
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answer #1
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answered by Ultraviolet Oasis 7
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To someone watching time would stop, [if] you saw a ship heading for a black hole, you'd never see it enter, as light cannot escape a black hole. Once past the event horizon the light wont go anywhere, so the ship will appear to just freeze where it is, and never move again.
Of course you cant see black holes because light cannot come off of them.
Noone knows whats past the event horizon.
General/Special relativity states that there is a possibility of a singularity. An area of 0 dimensions every direction, but with unlimited mass, which would explain the huge amounts of gravity.
2007-10-19 10:49:37
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answer #2
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answered by Anonymous
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The singularity of a black hollow technically would not have a "middle" through fact the singularity itself is a element. that's infinitely small, and for this reason has countless density. the severe turbulence brought about by potential of the gravity and mass of the singularity creates the "adventure horizon", a sphere around the singularity. it is the element of no longer return. If something is going in previous the form horizon, even gentle, it is going to likely be compressed into countless density. A black hollow would not have countless gravity, through fact countless gravity might require inifnite mass, which a black hollow would not have. Mass from a black hollow is continually released as Hawking Radiation. So, at one element, a marble could have greater mass and for this reason gravity than a black hollow. with the intention to get an theory of the size of the singularity, think of a pinhead. Now make it one hundred situations smaller. Now make it one hundred million situations smaller. do this a pair trillion situations greater. Now do this some octillion situations greater. you're an limitless quantity of situations greater effective than the singularity of a black hollow. In different words, a singularity is the smallest length something may well be without no longer latest.
2016-10-13 05:06:35
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answer #3
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answered by ? 4
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There are two conditions under which time can't exist, one is for anything moving at the speed of light, the other is where there is no space. Time is defined as an interval between events, events require movement, movement requires space. Inside a black hole there is no space between the tightly packed particles, therefore there can be no time.
2007-10-20 05:07:05
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answer #4
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answered by johnandeileen2000 7
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In one interpretation of the space-time equations of General Relativity it does appear that way. But the whole of 'normal' Physical reality is so weirdly screwed around and twisted inside a Black Hole that nobody really knows for sure.
Same thing for a photon. It travels at the speed of light (by definition) so does time not exist for photons? Do they 'see' the entire Universe (and all of space-time) as a single 'point'?
Doug
2007-10-19 09:07:54
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answer #5
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answered by doug_donaghue 7
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All the watches are squished.
But time continues. You cannot affect space-time without time.
2007-10-19 09:13:09
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answer #6
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answered by Phoenix Quill 7
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