A rectangle has a width that is 2 more than three times the lenght. The perimeter measures 92 units.
2007-10-19 08:06:17 · 8 answers · asked by davidiscool@sbcglobal.net 2 in Science & Mathematics ➔ Mathematics
2*w+2*L = 92 ....(1)
and
w = 2+3*L ....(2)
Plug the (2) into (1)
2*(2+3*L)+2*L = 92
solve for L
L = 11
Now plug this into (2)
w = 35
2007-10-19 08:11:09 · answer #1 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 0⤊ 0⤋
Let the length of the rectanglebe L
& the width of the rectangle be B
perimeter = 92
perimeter= 2(L+B)
B=2+3L
substitute this in the perimeter formula
92= 2[L+(2+3L)]
92=2[L+2+3L]
92 = 2[4L+2]
92/2 = 4L+2
46 = 4L+2
46-2 =4L
44 = 4L
11 = L
B=2+3L
B= 2+3(11)
B= 2+33
B= 35
2007-10-19 08:18:34 · answer #2 · answered by Siva 5 · 0⤊ 0⤋
perimeter = 2L x 2W
let length = x
let width = 3x+2
92 = 2(x) + 2(3x+2)
92 =2x +6x+4
88=8x
x=11
length = 11 units
width = 3(11) +2 = 33 +2 = 35 units
2007-10-19 08:14:03 · answer #3 · answered by Sheep Herder 3 · 0⤊ 0⤋
let l be the length
w = 3l+2
P = 2l + 2w = 2l +2(3l+2) = 92
2l + 6l + 4 = 92
8l = 88
l = 11
w = 33+2 = 35
check: 2(11+35) = 92
2007-10-19 08:12:37 · answer #4 · answered by norman 7 · 0⤊ 0⤋
W = 3L + 2
P = 2L + 2W
92 = 2L + 2(3L + 2)
92 = 2L + 6L + 4
88 = 8L
L = 11
W = 3L + 2 = 33 + 2 = 35
width = 35, length = 11
2007-10-19 08:12:33 · answer #5 · answered by Marvin 4 · 0⤊ 0⤋
Perimeter = 2L + 2W
W = 2 + 3L
so P = 2L+ 2(2+3L)
= 2L + 4 + 6L
= 8L + 4
We're told P = 92 so
92 = 8L + 4
8L = 88
L = 11
Since W = 2 + 3L then
W = 2 + 33
= 35
CHECK:
2L = 22
2W = 70
2L + 2W = 92
2007-10-19 08:10:56 · answer #6 · answered by PeterT 5 · 0⤊ 0⤋
w = 3l + 2
perimeter = 2(l+w) = 2(l +3l+2) = 2(4l+2)
so 2(4l+2) = 92
4l+2 = 46
4l = 44
l = 11
w = 35
2007-10-19 08:13:18 · answer #7 · answered by mohanrao d 7 · 0⤊ 0⤋
2L + 2w = 92
L + W = 46
L + 3L + 2 = 46
4L = 44
L = 11
W = 35
2007-10-23 07:01:27 · answer #8 · answered by Como 7 · 0⤊ 0⤋