3 consecutive even integers are so that the sum of the 2 larger integers is 232 more than 3 times the smallest integer.
2007-10-19 07:38:15 · 3 answers · asked by crystalie t 1 in Science & Mathematics ➔ Mathematics
even integers are 2 apart
Thus, x = smallest
x + 2 = next
x + 4 = largest
sum of the 2 larger would be 2x +6
This is 232 more than 3 times the smaller
2x + 6 = 3x + 232
Solve for x
2007-10-19 07:45:07 · answer #1 · answered by Linda K 5 · 0⤊ 0⤋
let (x-2), x and (x+2) are consecutive even integers
from the given information
x + x+2 = 3(x-2) +232
2x+2 = 3x-6+232
-x = 226 -2
x = -224
the numbers are
-226, -224, -222
2007-10-19 07:51:45 · answer #2 · answered by mohanrao d 7 · 0⤊ 0⤋
let n be the smallest integer, then n+2 and n+4 are the next two number.
n+4 + n+2 = 3n + 232
2n + 6 = 3n +232
n = -226
the three numbers are -226, -224 and -222
2007-10-19 07:45:42 · answer #3 · answered by norman 7 · 0⤊ 0⤋