sorry guys, another simultaneous equation I am having problems with?

Question

2p-5q=5
3p-2q=-9

many thanks to anyone who can help x

Answer 1

If you solve the second equation for p you would end up with p=-3+(2/3)q. So plug that in for p in the first equation. It should look like this

2(-3+(2/3)q)-5q=5

Then you can solve for q.......once you have that you can plug your value for q back into either equation and solve for the real value of p.

This is called substitution because you are substituting the value of p for an expression that represents the value of p.

Answer 2

2p-5q=5
3p-2q=-9
Multiply 1st Eq by 3 and 2nd Eq by -2 getting:
6p - 15q = 15
-6p +4q =18
Ad the above Eqs getting:
-11q = 33
q = -3
3p -2(-3) =-9
3p +6 = -9
3p =-15
p = -5

Answer 3

2p-5q=5
3p-2q=-9

Multiplies the (2) of the first equation, for the second equation, this is: = 6p - 4q =-18

Multiplies the (3) of the second equation for the first equation, this is: = 6p - 15q =15.

6p - 15q =15
-(6p -4q = -18)

0p -11q = 33

33/-11 = -3
q = -3 minus 3
p = -5 minus 5

check it!

Answer 4

well, 2p= 5q + 5
divide by 2 onn both sides
p=2.5q + 2.5
then add the 2.5 together
p=5q thats as far as i can get it

nexxt one
3p-2q=-9
add the 2q
3p=2q -9
divide by 3
p=.66666q -9
thats as far as i got ont his one.

hope this helps and good luck

Answer 5

2p-5q=5 is the same as 2p-5q-5=0
3p-2q=-9 is the same as 3p-2q+9=0

So 2p-5q-5=3p-2q+9
So 2p-3p-5q+2q-5-9=0
Simplifys to -p-3q-14=0
So p= -3q-14

Substitute 'p' in:-

2(-3q-14)-5q=5 becomes -6q -28 -5q =5
so -6q-5q=5+28 is the same as -11q = 33
So q= -3

3p-2(-3)= -9 Which becomes 3p+6=-9 (double negative)
So 3p= -15 p= -5

Answer 6

multiply the first equation by 3 gives
6p-15q=15
Multiply the second by 2 gives
6p-4q=-18
Subtract 2nd from 1st gives
-11q=33
or q=-3
in the 1st equation
2p-5(-3) =5 or 2p=5-15 or p=-5

Answer 7

the entire value of the stamps is 2568 cents. to artwork out the value of the 40 8 cent stamps, we multiply by potential of x. comparable applies for 60 and y. So one equation reads: 48x + 60y = 2568 the entire form of stamps is far less complicated. x + y = 50. particularly that became the difficult bit. then you definately multiply the 2d equation so as which you will subtract it from the former, for this reason removing a variable. I instinctively chosen 60 - this makes the y variables equivalent and for this reason subtractable, plus 60x50 is effective and around. (x+y=50) * 60 = 60x+60y=3000 then subtract the different equation: (60x + 60y = 3000) - (48x + 60 y = 2568) = 12x=432 x=432/12 x=36 and you may could desire to be exceedingly dense to wish from now on assistance.

Answer 8

SIMPLY LAYED OUT:

2p-5q=5 eq.1
3p-2q=-9 eq.2

eq.1 x 3 and eq.2 x 2
6p-15q=15 eq.3
6p-4q=-18 eq.4

Eq.3 - eq.4
-11q=33

q= -3

Then put q into equation to work out p:
3p-(2x-3)=-9
3p=-15

p= -5

Answer 9

From the first equation, p=(5q+5)/2
Plug that into the second equation and you'll find "q"
Then you can find "p"

Simple when you understand the concept.

Answer 10

ollie_ho provides the correct solution. The - sign in -9 was easily overlooked. By using elimination, ollie's solution is the most elegant.Opps! Ollie forgot the - sign at the end. p=-5.