How would I find the limit of (10/9^n)+26arctan(n^7)?

1 ⤊

2007-10-19 05:50:03 · 3 answers · asked by tchoxi2000 1 in Science & Mathematics ➔ Mathematics

First term -> 0
Second term ->26*Pi/2 = 13*Pi
Sum -> 13*Pi

2007-10-19 06:01:13 · answer #1 · answered by Alexey V 5 · 1⤊ 0⤋

If you want the Limit n approaches Ï/2 from the right
or do you what the limit as n aproaches infinity,
or possibly something else.

2007-10-19 06:02:12 · answer #2 · answered by Peter m 5 · 0⤊ 2⤋

first summand==>0
2nd summand ==>26*pi/2=13pi so the limit is 13*pi

2007-10-19 06:38:53 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋