2007-10-19 05:28:41 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Should question be:-
(2x) (4x² - 3x - 1)
-----------------------
(4x + 1)
(2x)(4x + 1)(x - 1)
----------------------
(4x + 1)
(2x)(x - 1)
2007-10-19 10:55:40 · answer #1 · answered by Como 7 · 1⤊ 0⤋
Multiply 4x + 1 by 2x^2
You'll get 8x^3 + 2x^2
Subtract it from 8x^3 - 6x^2 + 2x
You'll get -8x^2 + 2x
Multiply 4x + 1 by - 2x
You'll get -8x^2 - 2x
Subtract it from -8x^2 + 2x
You'll get 4x
Subtract 1*(4x + 1) from 4x
You'll get -1
Now, add all factors you've multiplied by 4x + 1
(4x + 1)(2x^2 - 2x + 1) - 1 = 8x^3 - 6x^2 + 2x
2007-10-19 12:48:05 · answer #2 · answered by Amit Y 5 · 0⤊ 1⤋
(8x^3 - 6x^2 + 2x)/(4x+1)
To solve this problem, you may firstly fatorate the 1st expression:
= [2x . (4x^2 - 3x + 1)] / (4x +1)
= [2x . (x - 1)(4x + 1)] / (4x + 1)
Then, you have to simplify the similar therms:
= 2x . (x - 1)
= 2x^2 - 2x
2007-10-19 12:35:32 · answer #3 · answered by Anonymous · 2⤊ 2⤋
2X^2 - X
2007-10-19 12:32:43 · answer #4 · answered by Tiramysu 4 · 0⤊ 2⤋
the answer is 485 i did it with a scintific calc.
2007-10-19 12:32:29 · answer #5 · answered by ThatDude 2 · 0⤊ 2⤋
-6x
2007-10-19 12:31:48 · answer #6 · answered by Anonymous · 0⤊ 2⤋