factorize 14x^2y-21xy^3 and a^2-4a+3?

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2007-10-19 03:08:50 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

(7 x y )( 2 x - 3 y ² )

(a - 3)(a - 1)

2007-10-19 06:34:12 · answer #1 · answered by Como 7 · 0⤊ 0⤋

14x^2y - 21xy^3 has a GCF of 7xy to factor out
=7xy(2x - 3y^2)

a^2 -4a + 3 = (a - 1)(a - 3)

2007-10-19 10:13:18 · answer #2 · answered by Linda K 5 · 0⤊ 0⤋

14x^2y-21xy^3 = 7xy(2x-3y^2)
a^2-4a+3 = (a-3)(a-1)

2007-10-19 10:13:55 · answer #3 · answered by pro 2 · 0⤊ 0⤋

the answer for the first equation is 7xy(2x-3y^2) and for the second (a-1)(a-3)

2007-10-19 10:20:35 · answer #4 · answered by rcntrodriguez 2 · 0⤊ 0⤋

7xy(2x-3y^2)

(a-1)(a-3)

2007-10-19 10:22:05 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋