(1)8m+3=5m+15(2)2/3t-7=5-2/3t(3)3/4+1/2=1/3x-1/4(4)4(x+3)-5=7(x-1)+9(5)6(4+y)-3=4(y-3)+2y?

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(1)8m+3=5m+15(2)2/3t-7=5-2/3t(3)3/4+1/2=1/3x-1/4(4)4(x+3)-5=7(x-1)+9(5)6(4+y)-3=4(y-3)+2y?

my questions are 5question

2007-10-18 18:53:10 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

Question 1
3m = 12
m = 4

Question 2
2t - 21 = 15 - 2t
4t = 36
t = 9

2007-10-19 08:04:00 · answer #1 · answered by Como 7 · 1⤊ 0⤋

Use substitution. Solve the first equation for x by subtracting 2y x= 3- 2y Now plug 3- 2y in for x in the second equation 4y - 3 (3- 2y)= 1 4y- 9 + 6y = 1 10y= 10 y=1

2016-05-23 15:48:44 · answer #2 · answered by ? 3 · 0⤊ 0⤋

um..i can't read all your questions... but first one...

1. 8m+3 = 5m + 15
solve for m: 8m - 5m = -3 + 15

3m = 12
m = 4

2007-10-18 18:58:07 · answer #3 · answered by phil h 2 · 0⤊ 0⤋