need help with corrections with vertical asymptotes--i choose best answers!!?

Question

(2x-2) / ( (x-1)(x²+x-12) )

becomes

(2x-2) / (x³-13x-12)

becomes

(2x-2) / ( x(x-1)(x-12)

giving me vertical asymptotes at x= -1 and -12??

Answer 1

(2x-2) / ( (x-1)(x²+x-12) ) =
2(x-1) / ( (x-1)(x-3)(x+4)) =
2 / ((x-3)(x+4))

There are 2 vertical asymptotes
one at x = 3 and another at x = -4

Answer 2

your vertical asymptotes are in your denominator, and you set each set equal to 0:

x=0
x-1=0 => x=1
x-12=0 => x=12

So you actually have 3 of them at 0, 1, and 12

EDIT: lol... demiurge42 is right. I should have checked your factoring. I just continued your solution. :)