A flowerpot falls from a windowswill 37.3m above the sidewalk. a)What is the velocity of the flowerpot when it

Question

strikes the ground. Answer in units of m/s.

b)How much time does a passerby on the sidewalk below have to move out of the way before the flowerpot hits the ground? Answer in units of m/s.

I'm having a hard time figuring out what formulas to use and how to plug everything into the formula so any help would be greatly appreciated.

Answer 1

acceleration is 9.80 m/s
change in distance is 37.3 meters
initial velocity is 0 m/s

Hope this helps? Try using an equation that contains this data.

Answer 2

This is the same question a the one you asked about the robot dropping the camera on Mars.
And you solve it -exactly- the same way (except that you use 9.8 m/s² for Earths gravitational acceleration)

And how do you answer how long the pedestrian has to get out of the way in units of m/s? Why not liters or kilograms?

Doug

Answer 3

displacemet = 37.3m
initial velocity = 0 m/s
acceleration = 9.8 m/s^2
final velocity = ??

use formula: Vf^2 = Vi^2 + 2ad

Vf^2 = (0)^2 + 2(9.8m/s^2)(37.3m)
Vf^2 = 731.08 m2/s2
Vf = square-root(731.08m2/s2)
Vf = 27.0 m/s

Therefore velcity as it strikes the ground is 27.0 m/s

b)now u hav the initial velocity = 0
acceleration = 9.8 m/s2
final velocity = 27.0m/s
time = ??

formula: a = (Vf - Vi) / t

rearrange for t
t = (Vf - Vi) / a
t = (27.0m/s - 0m/s) / 9.8 m/s2
t = 27.0m/s / 9.8 m/s2
t = 2.8 s

Therefore, the dude at the bottom will hav 2.8 s to get out of the way

Answer 4

Okay, for part A, the rate of free fall is the same no matter the mass. While, upwards force would be caused from air friction, it would be basically the rate of free fall - 9.8 m/s.

Part b, 37.8m divided by 9.8 m/s is equal to 3.8 s.