I'm having real problems trying to understand neutralizarion reactions. For example...
How many mL's of 0.200 M (molarity) HCL are required to neutralize 10.0 mL of 0.200 M Ba(OH)2
help is greatly appreciated
2007-10-18 16:49:22 · 2 answers · asked by millie1615 1 in Science & Mathematics ➔ Chemistry
Ba(OH)2 + 2 HCl = BaCl2 + 2H2O
From the equation, you can see it takes 2 parts of HCl to neutralize one part of Ba(OH)2. Since both solutions are 0.2M, 20 ml of HCl is required to neutralize 10 ml Ba(OH)2.
2007-10-18 16:58:07 · answer #1 · answered by OKIM IM 7 · 0⤊ 0⤋
In neutralization, each H+ is matching up with an OH-. Although the two solutions have the same molarity, the barium hydroxide has twice the OH- concentration as the HCl has H+ concentration, so you'll need twice as much HCl solution, or 20.0mL.
2007-10-19 00:02:35 · answer #2 · answered by chem.lady 3 · 0⤊ 0⤋