please help with math?

Question

1
_x - 5=27
4

How do i do this problem

Answer 1

add 5 to both sides:
1/4x = 32
multiply by 4:
x=128

Answer 2

The object of this type of problem is to rearrange the elements of the equation so that the variable (x, in this case) is on one side of the = sign and the remainder is on the other side. I would first start by adding 5 to both sides of the equation, yielding 1/4x = 27+5 = 32. Then, divide both sides by 1/4 (same as multiplying by 4), which yields x = 32*4 = 128. Therefore x=128. To check your work, plug 128 into the original equation for x and do the math... 128 * 1/4 = 32, 32 - 5 = 27. It checks out.

Answer 3

if the ? is "1fourth x, minus 5 equals 27, then to solve the problem:

add 5 to both sides to get rid of the 5
1/4x=32

then multiply both sides by 4/1 or 4 to get rid of the 1/4 in front of the x
x=128

Answer 4

OK - I think you are trying to say this:

(1/4 x) - 5=27; OK - let's multiply each side by 4.
x -20 = 108
x = 128

Now let's check:

1/4(128) - 5 = 27??
32 -5 = 27??
27 = 27 YES!

Hope this helps.

Answer 5

add 5 to 27 = 32
then you get 1/4 x = 32 so multiply by 4 and get 128

x=128

Answer 6

you multiply 5 and 27 by 4.
x - 20 = 108

find x.
x = 108 + 20
x = 128

Answer 7

1 x - 5 = 27
4

Add 5 to both sides of the equation:
1
--- x = 32
4

Multiply both sides of the equation by 4:
x = 128

Answer 8

(1/4)*x - 5 = 27
Add 5 to both sides to isolate (1/4)*x
(1/4)*x - 5 + 5 = 27 + 5
(1/4)*x = 32
Multiply both sides by 4 to find the value of x
4*(1/4)*x = 4*32
x = 128

Hope that helps.

Answer 9

1/4x - 5 = 27
-5 + 5 = 0
27 + 5 = 32
1/4x = 32
32/(1/4)
x = 128

Answer 10

1/4x - 5 = 27
+5 +5
1/4x=32
Divide each side by 1/4
x = 128