M is the midpoint of PQ. If PM=5x2 and PQ=160, which of the following is a valid solution for x?

Question

M is the midpoint of PQ. If PM=5x2 and PQ=160, which of the following is a valid solution for x?

4

5.7

16

80

Answer 1

Im guessing that 5x2 means 5x squared, being that, the answer is 4, since pm is half pq, 160 divded by 2 = 80, 80 divided by 5 = 16 and the square root of 16 is 4. Being that The answer is 4

Answer 2

PM = a million/2 PQ = a million/2 (one hundred sixty) = 80 PM = 5x^2 = 80 x^2=16 or x=4 2d situation, no longer particular about the ratio. yet searching at a drawing of the divided line it sounds as if the three:2:6 skill there is 11 aspects and also you opt for to understand what's 8 out of the 11 or 8/11 which represents BD. the finished is ad =88 so 8/11 of 88 is sixty 4. very last answer: BD=sixty 4 very last situation: AB+BC=AC x^2+9x=36 or x^2+9x-36=0 provides (x+?)(x-?)=0 giving (x+12)(x-3)=0 putting each and every fator to 0 provides: x=-12 or x=3 the answer it really is smart is x=3 and BC= 9(3)=27 BC won't be able to be 9(-12)=-108; would not make sense.

Answer 3

Assuming that 5x2 is 5 times X-squared, the solution is:

5(X^2) = 80

X^2 = 16

X = 4

Answer 4

none of the above.
x= 8


NB: is PM = 5x2 =10x
since PM = MQ
10x = 160/2
10x =80
x=8

either that or there is a confusion with 5x2


edits-
oh yeah if it is 5 x^2 then x = 4