A 2:35 kg block is pushed 1.57 m up a vertical wall with constant speed by a constant force of magnitude F app

Question

A 2:35 kg block is pushed 1.57 m up a vertical wall with constant speed by a constant force of magnitude F applied at an angle of 67:5 degree with the horizontal. The acceleration of gravity is 9.8 m/s2. If the coefficient of kinetic friction between the block and wall is 0:678, and the work done
by F. Answer in units of J.

Answer 1

μ = 0.678; d = 1.57 m; theta = 67.5 deg; m = 2.35 kg;
g = 9.8 m/s^2
Fnormal = Fcos(theta)
Ffric = Fnormal*μ
Work = d*(mg + Ffric) J

Answer 2

First, enable's discover the cost of F. because of the fact the fee is persevering with, the sum of forces is 0 m*g-F*cos(30)*.3=F*sin(30) sparkling up for F F=(5*9.8)/(sin(30)+cos(30)*.3) F=sixty 4.5 N The paintings accomplished by skill of the stress is F*sin(30)*4+F8cos(30)*.3*4 =196 J Gravity is -196 J widely used stress is 0 PE larger by skill of 196 J