A spherical glass container of unknown volume contains helium gas at 25°C and 1.850 atm. When a portion of the helium is withdrawn and adjusted to 1.00 atm at 25°C, it is found to have a volume of 2.00 cm3. The gas remaining in the first container shows a pressure of 1.710 atm. Calculate the volume of the spherical container.
ml
can you please show me how?
2007-10-18 15:05:52 · 1 answers · asked by My point exactly 5 in Science & Mathematics ➔ Chemistry
I think that the shape of the glass container is not relavent, spherical or cylindrical or cubical or whatever!
Use ideal gas law on the portion of the helium withdrawn, and let the partial pressure of this portion of He in the big glass container to be 1.850 atm - 1.710 atm = 0.140 atm:
PV = pv
V = pv/P = 1.00*0.00200/0.140 = 0.0143L
The volume of the spherical container is 0.0143L.
2007-10-18 16:23:14 · answer #1 · answered by Hahaha 7 · 1⤊ 0⤋