English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2 identical loudspeakers ar eplaced ona wall 2m apart. A listener stands 3m from the wall directly in front of one the speakers. A single oscillator is driving the speakers at a frequence of 300Hz.
a) what is the pahse different b/w the two waes when the reach the observer?

2007-10-18 13:33:18 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

Calculate the distances from the speakers, divide that by hte propagation velocity of sound, and that gives the time difference. Now use the time difference to calculate the phase difference at 300 Hz and you're done.
Alternatively, you can calculate the wavelength of the wave in the air at 300 Hz and then use the difference in distance to calculate the phase difference. You'll get the same answer either way.

Doug

2007-10-18 13:44:06 · answer #1 · answered by doug_donaghue 7 · 0 0

fedest.com, questions and answers