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A pitcher throws a baseball horizontally from the mound to home plate. The ball falls 0.918 m (3.01 ft) by the time it reaches home plate 18.3 m (60 ft) away. How fast was the pitcher's pitch?
(answer in m/s)

2007-10-18 13:06:35 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Calculate how long it would take for the ball to drop .918 meters. Then divide that into 18.3 meters to get the speed in m/s.

Doug

2007-10-18 13:25:18 · answer #1 · answered by doug_donaghue 7 · 0 0

13.4 m/s

I used d = a*t^2, a = 9.8 m/s^2, solved for t, then divided 18.3/t.

2007-10-18 20:11:32 · answer #2 · answered by Anonymous · 0 0

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