Here is the problem.
Is 1 over 3 (fraction) a solution of z + 4 over 2 - z (fraction) = 13 over 5 (fraction)
I can not figure out how to find the answer. I don't know what do with the fraction's. Can someone show me? Thank you!
2007-10-18 13:03:55 · 2 answers · asked by Here Is Holly. 1 in Science & Mathematics ➔ Mathematics
(z + 4) / (2 - z) = 13/5
5(z + 4) = 13(2 - z) ==> cross multiplication
5z + 20 = 26 - 13z
18z = 6
z = 6/18
z= 1/3
The solution is correct.
2007-10-18 13:11:24 · answer #1 · answered by Lucky 4 · 0⤊ 0⤋
The key to solving this problem to know that you can cross multiply fractions across the equal sign. That is, left numerator * right denominator = left denominator * right numerator.
(z+4)/(2-z)=13/5 original quation
5(z+4)= 13(2-z) cross multiply
5z+20=26-13z remove the parenthesis
5z+13z=26-20 move z term to one side
18z=6 simplify
z=1/3 divide both sides by 18
2007-10-18 13:14:07 · answer #2 · answered by tkquestion 7 · 0⤊ 0⤋