A physicist on planet Mongo is using a device equivalent to Atwood's machine to measure the Mongoian gravitational acceleration gm. He fixes one of the two 0.40kg masses at each end of the rope. While both are at rest, he places a 0.025kg gronch (a toadlike creature) on one of the masses. That body and its wart-covered passenger descend 0.50m before the gronch hops off. The body continues traveling downward another 0.8m in the next 3.0s. Compute gm.
please help me with the question.
I'm stuck for hours on this.
2007-10-18 12:36:13 · 2 answers · asked by Seongmo L 1 in Science & Mathematics ➔ Physics
You know when toad jumps v =.8/3
You know that v=at so t=v/a where a is net acceleration
from the formula for distance
,5=1/2at^2 =1/2 av^2/a^2 = 1/2v^2/a so a=v^2
then use formula relating acceleration and gravity for Atwood machine to find g http://hyperphysics.phy-astr.gsu.edu/hbase/atwd.html
2007-10-18 13:36:04 · answer #1 · answered by meg 7 · 0⤊ 0⤋
The Gronch
2016-11-13 04:01:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋