We were assigned these problems to do for homework where we're supposed to find the zeros of these equations (cubic, quartic, all those). I did all the synthetic division and all that, did all the stuff, but then got stuck!
So my question is:
Is the Square root of -19, 19i ?
I thought I was right, but someone told me otherwise.
Am I right? If not, can you explain what the correct answer is and how you got it?
Thanks.
2007-10-18 12:30:13 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
No:
√-19 = (√19)i ≈ 4.35889i
Just like:
√-16 = (√16)i = 4i
2007-10-18 12:47:08 · answer #1 · answered by jsardi56 7 · 0⤊ 0⤋
Pull out the unfavorable from the finished equation: s = -(16t^2-63t-4) because 16*-4+a million=-sixty 3, your factoring might want to be : s = -(16t+a million)(t-4) because you top s, is at 0, placed s=0 0= -(16t+a million)(t-4) t= -a million/16 or t=4, because you won't be able to have the unfavorable time, t= -a million/16 is dismissable, as a effect, the time at the same time as the ball will hit the floor is t=4s
2016-10-21 09:32:36 · answer #2 · answered by ? 4 · 0⤊ 0⤋
I think your answer is correct. I haven't had precalculus in a while but if I remember correctly I believe that i is equal to -1 and when you multiply two negatives together it equals a positive so I think your answer of 19i is correct.
2007-10-18 12:44:48 · answer #3 · answered by bratz girl 21 2 · 0⤊ 1⤋
I think that's right...I'm only in algebra II, but I know about derivatives, limits etc.
2007-10-18 12:38:09 · answer #4 · answered by Dan 3 · 0⤊ 1⤋