Please help Calc 2 Integration of sin^4xcos^2x dx?

Question

I need to know the integration of sin^4xcos^2x (the x is not in the exponents) its part of the sin and cos

I have

(.5(1-cos2x))^2 * (.5(1+cos2x))
1/8 ( 1-cos^2(2x))(1-cos2x) dx

stuck please help!

Thanks,

Sarah

Answer 1

Replace cos^2x with 1 -sin^2x
Then the integrand becomes sin^4x - sin^6x which you soud be able to easily integrate.