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A ray of light traveling in material A strikes the interface between materials A and B at an angle of incidence of 65.3 . The angle of refraction is 39 . Find the ratio nA/nB of the refractive indices of the two materials

2007-10-18 10:46:05 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

Snell's law states: nA/nB = sin(thetaB)/sin(thetaA) (ref.)
The angles of incidence and refraction are the angles the rays make to a line normal to the interface.
nA/nB = sin(39 deg)/sin(65.3 deg)

2007-10-18 15:32:59 · answer #1 · answered by kirchwey 7 · 0 0

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