please explain...
2007-10-18 08:49:54 · 8 answers · asked by me 3 in Science & Mathematics ➔ Mathematics
I feel dumb now....one of those duh moments. Thanks a lot.
2007-10-18 08:54:48 · update #1
(y^2 + 8)(y^2 - 3) = 0
2007-10-18 08:53:16 · answer #1 · answered by Anonymous · 1⤊ 0⤋
if x = y^2, then your equation becomes this:
x^2 + 5x - 24 = 0
Can you solve it now? You have to find the factors of 24 whose difference is +5. (You have to do the difference because 24 is negative -- if it were positive, you would have to do the sum)
1 & 24 ----- the difference is +/- 23
2 & 12 ----- the difference is +/- 10
3 & 8 ---- the difference is +/- 5 <=== there you go
4 & 6 --- the difference is +/- 2
8 - 3 = +5 <== so I want +8 & -3
3 - 8 = -5
(x + 8)(x - 3)=0
substitute the y^2 back in and get
(y^2 + 8)(y^2 - 3) = 0
I hope that helps!
2007-10-18 16:01:16 · answer #2 · answered by nc 3 · 0⤊ 0⤋
(y^2 + 8)(y^2 -3) = 0
2007-10-18 15:55:12 · answer #3 · answered by T 5 · 0⤊ 0⤋
y^4 + 5y^2 - 24 = (y^2 + 8)(y^2 - 3). If you want to go further, you'll have to use square roots on the right-hand factor: y^2 - 3 = (y + sqrt(3))(y - sqrt(3)).
2007-10-18 15:55:12 · answer #4 · answered by TurtleFromQuebec 5 · 2⤊ 0⤋
(y^2 + 8)(y^2 - 3)
2007-10-18 15:55:15 · answer #5 · answered by papastolte 6 · 1⤊ 0⤋
(y^2 + 8)(y^2 - 3)
2007-10-18 15:54:13 · answer #6 · answered by fcas80 7 · 1⤊ 0⤋
Hi, check out this websight it might have some answers and has got some example on how to solve problems like it. hope this helps a little.
http://www.mathnstuff.com/math/algebra/asystem.htm
2007-10-18 15:59:43 · answer #7 · answered by git_errr_dun 1 · 0⤊ 0⤋
( y ² + 8 ) ( y ² - 3 ) = 0
y = ± i â(8) , y = ±â3
2007-10-18 18:04:54 · answer #8 · answered by Como 7 · 0⤊ 0⤋