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A physics student playing with an air hockey table (a frictionless surface) finds that if she gives the puck a velocity of 3.80 m/s along the length(1.75 m) of the table at one end, the puck has drifted 2.50 cm to the right but still has a velocity component along the length of 3.80m/s. She correctly concludes that the table is not level and correctly calculates its inclination from the above information. What is the angle of inclination?

2007-10-18 08:46:08 · 2 answers · asked by selece_wingard 1 in Science & Mathematics Physics

2 answers

Transit time t = x/v = 1.75/3.80 s
Lateral acceleration a = 2s/t^2 = 0.05/t^2 m/s^2
Inclination = arcsin(a/g) rad

2007-10-18 15:20:53 · answer #1 · answered by kirchwey 7 · 0 0

you do not might desire to appreciate the mass. The coefficient of friction is the ratio of the frictionchronic to the common rigidity (rigidity properly-known to the exterior). the primarychronic exerted via an merchandise of weight X on a slope is X*COS(perspective). Thechronic parallel to the exterior is X*SIN(recommendations-set). With consistent-velocity sliding the frictionchronic equals the parallelchronic because of the load. So the coefficient of friction = X*SIN(perspective)/(X*COS(perspective)) = SIN(perspective)/COS(recommendations-set), or TAN(perspective).

2016-11-08 20:50:24 · answer #2 · answered by ? 3 · 0 0

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